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SOLVING LINEAR EQUATION USING SUBSTITUTION METHOD. July 2, 2008

Filed under: MATH — jhano @ 4:55 am
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1) x + 2y = -7 and 5x – 3y = 30

By substitution method:

Step 1. Find an equation to be used as a substitute to the other equation.

x + 2y = -7 –> x = -7 – 2y

Step 2. Substitute the equation to the other equation.

x = -7 – 2y

5x – 3y = 30

5 (-7 – 2y) – 3y = 30

-35 – 10y – 3y = 30

-10y – 3y = 30 + 35

-13y = 65 Divide by -13

y = -5

Step 3. Substitute -5 to y and solve the other variable.

x = -7 – 2y

x = -7 – 2(-5)

x = -7 + 10

x = 3

Step 4. Check

(3, -5)

x + 2y = -7 l 5x – 3y = 30

3 + 2(-5) = -7 l 5(3) – 3(-5) = 30

3 – 10 = -7 l 15 + 15 = 30

- 7 = – 7 l 30 = 30

Therefore the solution is (3, -5).

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